Aldehydes and ethylene glycol. The words sound like they belong in a chemistry lab, but what does it mean? An aldehyde is any of a class of organic compounds that are characterized by the presence of an alcohol group (CHO) attached to the carbon atom adjacent to the carbonyl group (-C=O). Ethylene glycol is also known as 1,2-dihydroxyethane or DHE. So, when you put these two together, you get products that could be used for many different purposes. In this article, we will explore how these two react with one another and what happens when they do so.
How to Draw the Major Product x When the Given Aldehyde Is Treated with Ethylene Glycol in Acid
Explanation:
The first thing needed is an example of an aldehyde – formaldehyde (HCHO). A molecule of formaldehyde has one hydrogen atom on its right side, three hydrogens on its left side, and four carbons between them all. You should also know about ethylene glycol – it’s also known as DHE. This molecule has one hydrogen atom on its left side, two hydrogens on the right side, and four carbons between them all.
Conclusion:
The major product x will be alcohol with aldehyde properties- that is to say, it would contain a C=O carbon double bond and may have other functional groups. Ethylene glycol reacts with formaldehyde in acid via either an alpha or beta elimination reaction (or both). Alpha eliminations occur when H+ ions are present; they remove the CHOH group from the original aldehyde leaving behind only COH as their product. If there aren’t any H+ ions around, then you’re dealing with beta eliminations which result in hydrolysis of ethylene glycol into water and glyoxal.
Writes about how to draw the major product x when the given aldehyde is treated with ethylene glycol in acid, formula related to it, and information
The major product will be alcohol with aldehyde properties that reacts via either alpha or beta elimination reaction (or both) If there are H+ ions around then you’re dealing with an alpha elimination which results in hydrolysis of ethylene glycol into water and glyoxal Alpha eliminations occur when H+ ions are present; they remove the CHOH group from the original aldehyde leaving behind only COH as their product.
If all is well, it should not take too long for one to draw out this particular chemical diagram.
Step One: draw the skeletal structure of ethylene glycol and show its OH groups (-O-).
Step Two: label our reactant x (*note: This is just an example to convey the general idea)
Step Three: draw out what is termed as a Bronsted-Lowry acid which in this case would be HCl.
Step Four: follow instructions from above (x + EG + H+(x) –> COH+HO-(x)) so that the end product will yield COH+HO-(x) which can also be written in a structural form as COOCHOHCOONa. The molecular weight for COOCHOHCOONa should total up to 246 g/mol with a molecular formula of C11H18N12O13.
So now that the major product x has been drawn out, one can also draw in some basic facts about this particular chemical reaction to have a better understanding of why it occurred
COH is produced by substitution as an acid catalyzes with ethylene glycol and water (HO) at -xv degrees Celsius.
As for equilibrium constants (+Kc), because HCl was used as the Bronsted Lowry acid, then Kc would be equal to .07/M which corresponds to +log(0.07*[H+]) = log(-0.34). And if outside factors are added into consideration such as temperature changes or variations in the concentration of ethylene glycol or HCl, then these can be used to calculate a new Kc value.
The reaction is not spontaneous and must meet certain conditions for it to occur successfully. Even with solutions that have less than 0.07 Molar concentrations of acid (H+), there will still need to be an excessive amount of water present in order for this reaction to happen at all because dissociation reactions are always favored over substitution ones
+Kc = -xv degrees Celsius, which means COOCHOHCOONa should form when x equals negative 18 degrees Celsius
Substitution reactions typically use Bronsted Lowry acids as they work best due to their ability to provide protons from the ionization of water
For example, when x equals negative 18 degrees Celsius and Kc = 0.18 Molar (mole fraction), this is the type of substitution reaction that will occur because it has a pH value below zero
