The x-coordinate of an object is measured in seconds, and the y-coordinate is measured in meters. If you know what time it was when the object reached a specific coordinate, then you can calculate its coordinates by using this formula:
x = (time) * t * 1000 / 3600; //s/m
y = height + (time) * t*1000/3600; // m
In order to get more accurate results from your calculation, use 100 as the denominator rather than 3600 for converting between seconds and minutes. The conversion process will now be equal to hours instead of days. This approach won’t give any new information but will make calculations much easier if there are many intervals of time.
what is the x-coordinate of an object when t = 20 seconds?
x = (time) * t*1000/3600; //s/m
y = height + 1000/(time)*t* 3600 ;// m
object’s x-coordinate is -13.69 meters when t= 20 seconds:
x=-(20) * 100 / 3650 == 13.69 meters”
In order to get more accurate results from your calculation, use 100 as the denominator rather than 3600 for converting between seconds and minutes. The conversion process will now be equal to hours instead of days.”This approach won’t give any new information but will make calculations much easier if there are many intervals of time.” “The coordinate system in Cartesian geometry includes an origin point at which two perpendicular lines intersect to form four quadrants. The coordinates of the object’s x-coordinate are -13.69 meters when t= 20 seconds.”
“Intersecting perpendicularly creates four separate regions or quadrants on a plane (x-axis). These quadrant divisions are numbered conventionally starting with I where 0 ≤ θ ≤ π/², II where π/² ≤ θ ≤ π, III where -π/² ≤ θ≤ 0 and IV where θ = π.”
“The coordinates of the object’s x-coordinate is 13.69 meters when t= 20 seconds.” “In mathematics, Cartesian geometry or Euclidean geometry takes its name from French mathematician René Descartes (1596–1650) who introduced this system to Western European mathematical science in 1637 with his publication of La Géométrie. The term comes from carte which means a drawing card,” “Euclid was an ancient Greek geometer whose Elements laid much of the foundation for classical plane geometry and number theory. His Elements begins with what is now called Euclidean postulates, five statements that form the basis for geometry”
In this article, we will explore the question: what is the x-coordinate of an object when t = 0.0 seconds?
We define time as a function of position on a plane or two-dimensional space. The equation for motion in one dimension (in which only speed and not direction are considered) can be presented by y(t)=y o +v*t+Δy where Δx=s d *dt; s is the distance traveled during interval dt and v is velocity with units meters/second. In other words, at each point along its trajectory, an object moves according to both its current speed and any forces acting on it from heretofore unmeasured sources such as air resistance, the shape of its trajectory, and so on.
The x-coordinate is always a positive distance from the origin (where objects are going up in y-direction). This means that when t = 0.0 s, an object’s position will be at this point:
x o +v*t+Δy=x o ; v*(0)+(Δy)=s d *dt; Δz=(s d *dt)/g; where g is acceleration due to gravity which has units meters/second^(-r), r being radius of earth with unit meters, we have that Δz=-g or -1000 m for t = 0.0 s . The conclusion is then that the x coordinate is always a positive distance from the origin.
*In case of an object moving in two-dimensions, it is not necessary to consider y coordinate so we will have that vx=dx/dt and vy=-dy/dt where dx=(s d *dt)/g; dy=-(1000 m)g for t = 0.0 s . The x-coordinate then becomes:
x o +vx+(Δz)=x o ; Δtz=(s d *dt)/g; Δtx=∫tεvdxt or ∫tεrtxdxt+∫tdydytdτwith τ being time interval with units seconds; since ≤r≤πwe have that Δtx=∫tεrtxdxt with r being radius of earth with unit meters and dx=(s d *dt)/g.
*In case the object is moving in one-dimension, it will be easier to consider x coordinate only:
x o +v(Δz)=x o ; Δtz=-g; δtdτ=∫tdy/dt where τ is time interval with units seconds so we have that δtdτ=-dy/dx or -1000 m for t = 0.0 s . The conclusion then becomes v≤dσdνor 1000≤800000m which leads us to ∂f=∂x when f is a function of x.
